Parallelogram Basics
What is a Parallelogram?
Parallelogram is a quadrilateral with two pairs of parallel sides.
- The opposite sides of a parallelogram are parallel and are of equal length.
- The opposite angles of a parallelogram are also equal. That is, ∠ A = ∠ C; ∠ B = ∠ D
Now, let us see some of the most well known parallelograms.
Rhombus
It is a Parallelogram that has all four sides of equal length.
It is also called as equilateral quadrilateral, because it has four equal sides (just as we call a triangle with three equal sides equilateral triangle).
So, Perimeter of a Rhombus = 4 × Side
Rectangle
It is a Parallelogram that has two diagonals of equal length, and all its four angles are right angles too (just like a square). However, only its opposite sides are equal.
So, its adjacent sides make an angle of 90° with each other.
AB = DC; BC = AD
AC = BD
∠ A = ∠ B = ∠ C = ∠ D = 90°
Perimeter of rectangle = 2 (length + breadth) = 2 (l + b)
Square
It is a Parallelogram that not only has all four sides of equal length (just like a rhombus), but all its angles are right angles too (just like a rectangle).
So, Perimeter of a Square = 4 × Side
Square - It is a Rectangle that has four sides of equal length.
That is, all of its four angles are 90° each, and all of its four sides are equal too.
So, in a way, square is a special case of rectangle.
In fact, Square is a Rectangle, as well as a Rhombus. However, vice-versa need not be true, i.e. a Rectangle or a Rhombus need not be a Square.
Properties of Parallelogram
These are the properties that are true for any kind of parallelogram.
Property 1: Angles
In a parallelogram, sum of any two consecutive angles is always supplementary.
In the above figure, ∠A + ∠B = ∠B + ∠C = ∠C + ∠D = ∠D + ∠A = 180°
In case of Rhombus: Pair of opposite angles are equal.
In case of Rectangle and Square: All angles are equal, as all angles are 90°.
Property 2: Diagonals
Property 2a
In a parallelogram, diagonals always bisect each other.
In the above figure, AO = OC; DO = OB
Property 2b
Each diagonal of a parallelogram bisects that parallelogram into two congruent triangles.
In the above figure, ∆ABD ≅ ∆CDB
Property 2c
Sum of squares of the sides of a parallelogram = Sum of the squares of its diagonals.
In the above figure, $AC^2 + BD^2 = AB^2 + BC^2 + CD^2 + DA^2$
However, in a parallelogram the opposite sides are equal. So, AB = CD, and BC = DA
So, $AC^2 + BD^2 = 2 (AB^2 + BC^2)$
In case of Rhombus:
- Diagonals are not equal in length.
- Diagonals bisect each other perpendicularly.
- Diagonals are angle bisectors.
Sum of the square of the diagonals = Four times the square of side, i.e. $d_1^2 + d_2^2 = 4 a^2$
In case of Square:
- Diagonals are equal in length (unlike Rhombus).
- Diagonals bisect each other perpendicularly.
- Diagonals are angle bisectors.
Diagonal of a square = $\sqrt{2}$ Side, i.e. d = $\sqrt{2}$ a
In case of Rectangle:
- Diagonals are equal in length (like Square, unlike Rhombus).
- Diagonals bisect each other (like Square and Rhombus), but not perpendicularly. (unlike Square and Rhombus)
- Diagonals are not angle bisectors. (unlike Square and Rhombus)
Diagonal of a rectangle = $\sqrt{l^2 + b^2}$
Property 3: Angle bisectors of Parallelogram
Property 3a
In a parallelogram, bisectors of any two consecutive angles make an angle of 90°.
In the above figure, ∠AOB = 90°
Property 3b
Bisectors of the four angles of a parallelogram form a rectangle.
In the above figure, PQRS is a rectangle.
However, there are a few properties that are true only for some specific kinds of parallelograms. Let’s see these too.
Property 4: Mid-point of sides
In case of Rhombus
Line segments joining midpoints of sides of a rhombus form a rectangle.
In the above figure, PQRS is a rectangle.
In case of Square
Line segments joining midpoints of sides of a square form a square.
In the above figure, PQRS is a square.
In case of Rectangle
Line segments joining midpoints of sides of a rectangle form a rhombus.
In the above figure, PQRS is a rhombus.
Property 5: In case of Rectangle
If P is some point inside of a rectangle, then:
$PA^2 + PC^2 = PB^2 + PD^2$